[OpenID] openid, foaf and groups
Story Henry
henry.story at bblfish.net
Wed Jul 25 21:02:04 UTC 2007
Sorry folks, I am a bit on a creative run here, and have published
one new post suggesting how one could
link openids to institutions using a few simple rdf relations. See:
http://blogs.sun.com/bblfish/entry/a_foaf_file_for_sun
I have posted this idea previously on the foaf list, but it is of
higher relevance to the openid list.
To summarize:
Sun microsystems OpenIds such as http://openid.sun.com/xxx are all
guaranteed to identify Sun employees. This is in
fact slightly misleading. What is really happening is that every id
that can be verified by
the server https://openid.sun.com/openid/service will be guaranteed
to be a Sun employee.
This made me realise that the openid service could in fact be used to
identify groups of Agents. Just as the
foaf:openid relation will identify a foaf:Agent, so I think we can
easily invent a openid:memberIdService relation that
will identify a foaf:Group, and provide a way to identify all the
members of the group without listing them.
As a result one could publish a foaf file for Sun Microsystems at
http://www.sun.com/sunw
------
<> a foaf:PersonalProfileDocument;
foaf:primaryTopic :sunw.
:sunw a foaf:Organization, foaf:Group;
foaf:name "Sun Microsystems"@en;
foaf:homepage <http://www.sun.com/>;
openid:memberIdService <https://openid.sun.com/openid/service>.
-------
By pointing an organisation to that resource, they would be
immediately have a way to identify all employees of Sun. So the W3C
could for example use this to allow Sun employees to log into special
areas of the W3C.
This is of course generalisable to every group.
I think this is neat because it both clarifies what an OpenId service
resource is, and opens up some very useful applications.
If people agree with this, should the openid group coin these
relations, or would the foaf group be the best place to do this?
Perhaps the foaf group could help the openid group with the task of
setting up an openid ontology. It should be really not that difficult
to do.
Henry
PS. I'll get back to answering some of the comments on my previous post.
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